[69] Sqrt(x)

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题目

Implementint sqrt(int x).

Compute and return the square root of_x_, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.

解法

一：使用Math.sqrt()方法

代码

class Solution {
    public int mySqrt(int  x) {
        return (int)Math.sqrt(x);
    }
}

二： 二分搜索

思路

二分搜索

代码

LeetCode.69.1.png


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